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<frontmatter>
<title>Simulation of Energy Loss Straggling</title>
<author>Maria Physicist</author>
<date>
August 7, 1998</date>
</frontmatter>
<bodymatter>
<section id="intro">
<stitle>
Introduction</stitle>
<par>Due to the statistical nature of ionisation energy loss, large fluctuations can occur in
the amount of energy deposited by a particle traversing an absorber element.
Continuous processes such as multiple scattering and energy loss play a relevant role
in the longitudinal and lateral development of electromagnetic and hadronic
showers, and in the case of sampling calorimeters the measured resolution
can be significantly affected by such fluctuations in their active layers. The
description of ionisation fluctuations is characterised by the significance parameter
<inlinemath><math>&kappa;</math></inlinemath>,
which is proportional to the ratio of mean energy loss to the maximum
allowed energy transfer in a single collision with an atomic electron
<displaymath><math>
                             &kappa;=   <frac> <nu> &xi;</nu><!--___
--><de>E<sub><mathrm>max </mathrm> </sub> </de> </frac>
</math></displaymath>
<inlinemath><math>E<sub><mathrm>max </mathrm> </sub> </math></inlinemath> is the
maximum transferable energy in a single collision with an atomic electron.
<displaymath><math>
                   E<sub><mathrm>max </mathrm> </sub> =          <frac> <nu> 2m<sub>e </sub> &beta;<sup>2 </sup> &gamma;<sup>2 </sup> </nu> <!--_____________
--><de>1+2&gamma;m<sub>e </sub> /m<sub>x </sub> +<left>( </left> m<sub>e </sub> /m<sub>x </sub> <right> ) </right> <sup> 2 </sup> </de> </frac>,
</math></displaymath> where
<inlinemath><math>&gamma;=E/m<sub>x </sub> </math></inlinemath>,
<inlinemath><math>E</math></inlinemath> is energy and
<inlinemath><math>m<sub>x </sub> </math></inlinemath> the mass of the
incident particle, <inlinemath> <math> &beta;<sup>2 </sup> =1-1/&gamma;<sup>2 </sup> </math></inlinemath>
and <inlinemath> <math> m<sub>e </sub> </math></inlinemath> is the
electron mass. <inlinemath> <math> &xi;</math></inlinemath>
comes from the Rutherford scattering cross section and is defined as:
             <eqnarray ><subeqn  
><math>&xi;=<frac><nu>2&pi;z<sup>2 </sup> e<sup>4 </sup> N<sub>Av</sub> Z&rho;&delta;x</nu><!--
     --><de>m<sub>e </sub> &beta;<sup>2 </sup> c<sup>2 </sup> A</de></frac>     =153.4 <frac> <nu> z<sup>2 </sup> </nu> <!--
--><de>&beta;<sup>2 </sup> </de> </frac> <frac> <nu> Z</nu><!-- 
--><de>A</de></frac>&rho;&delta;x   <mathrm> keV </mathrm> ,                 <mtext></mtext>
</math></subeqn></eqnarray>
where
</par><par><tabular preamble="ll"><row><cell  
><inlinemath><math>z</math></inlinemath></cell><cell  
>charge of the incident particle </cell>
</row><row><cell  
><inlinemath><math>N<sub>Av</sub> </math></inlinemath></cell><cell  
>Avogadro's number               </cell>
</row><row><cell  
><inlinemath><math>Z</math></inlinemath></cell><cell  
>atomic number of the material</cell>
</row><row><cell  
><inlinemath><math>A</math></inlinemath></cell><cell  
>atomic weight of the material </cell>
</row><row><cell  
><inlinemath><math>&rho;</math></inlinemath></cell><cell  
>density                               </cell>
</row><row><cell  
><inlinemath><math>&delta;x</math></inlinemath></cell><cell  
>thickness of the material        </cell>
</row><row><cell  
>                                                                  </cell>
</row></tabular>
</par><par><inlinemath><math>&kappa;</math></inlinemath>
measures the contribution of the collisions with energy transfer close to
<inlinemath><math>E<sub><mathrm>max </mathrm> </sub> </math></inlinemath>. For a given absorber,
<inlinemath><math>&kappa;</math></inlinemath> tends towards large
values if <inlinemath> <math> &delta;x</math></inlinemath> is large
and/or if <inlinemath> <math> &beta;</math></inlinemath> is small.
Likewise, <inlinemath> <math> &kappa;</math></inlinemath> tends
towards zero if <inlinemath> <math> &delta;x</math></inlinemath> is
small and/or if <inlinemath> <math> &beta;</math></inlinemath>
approaches 1.
</par><par>The value of <inlinemath> <math> &kappa;</math></inlinemath>
distinguishes two regimes which occur in the description of ionisation fluctuations
:
</par><lalist  class="enumerate">
<item>
<par>A large number of collisions involving the loss of all or most of the incident
particle energy during the traversal of an absorber.
</par><par>As the total energy transfer is composed of a multitude of small energy losses,
we                   can                   apply                   the                   central
limit theorem and describe the fluctuations by a Gaussian distribution. This
case is applicable to non-relativistic particles and is described by the inequality
<inlinemath><math>&kappa;&gt;10</math></inlinemath>
(i.e. when the mean energy loss in the absorber is greater than the maximum
energy transfer in a single collision).
</par></item>
<item>
<par>Particles traversing thin counters and incident electrons under any conditions.
</par><par>The relevant inequalities and distributions are <inlinemath> <math> 0.01&lt;&kappa;&lt;10</math></inlinemath>,
Vavilov distribution, and <inlinemath> <math> &kappa;&lt;0.01</math></inlinemath>,
Landau distribution.</par></item></lalist>
<par>An additional regime is defined by the contribution of the collisions
with low energy transfer which can be estimated with the relation
<inlinemath><math>&xi;/I<sub>0 </sub> </math></inlinemath>,
where <inlinemath> <math> I<sub>0 </sub> </math></inlinemath>
is the mean ionisation potential of the atom. Landau theory assumes that
the number of these collisions is high, and consequently, it has a restriction
<inlinemath><math>&xi;/I<sub>0 </sub> &greatermuch;1</math></inlinemath>. In <texttt> GEANT</texttt> (see
URL http://wwwinfo.cern.ch/asdoc/geant/geantall.html), the limit of Landau theory has
been set at <inlinemath> <math> &xi;/I<sub>0 </sub> =50</math></inlinemath>.
Below this limit special models taking into account the atomic structure of the material are
used. This is important in thin layers and gaseous materials. Figure <ref  
refid="fg:phys332-1"/> shows the behaviour
of <inlinemath> <math> &xi;/I<sub>0 </sub> </math></inlinemath> as
a function of the layer thickness for an electron of 100 keV and 1 GeV of kinetic
energy in Argon, Silicon and Uranium.
</par>
<figure>
<includegraphics file="phys332-1"/>
<!--Figure 1--><caption id="fg:phys332-1">The variable <inlinemath> <math> &xi;/I<sub>0 </sub> </math></inlinemath>
can    be    used    to    measure    the    validity    range    of    the    Landau
theory.    It    depends    on    the    type    and    energy    of    the    particle,
<inlinemath><math>Z</math></inlinemath>,
<inlinemath><math>A</math></inlinemath>
and the ionisation potential of the material and the layer thickness. </caption>
</figure>
<par>In the following sections, the different theories and models for the energy loss
fluctuation are described. First, the Landau theory and its limitations are discussed,
and then, the Vavilov and Gaussian straggling functions and the methods in the thin
layers and gaseous materials are presented.
</par>
</section>
<section id="sec:phys332-1">
<stitle>
Landau theory</stitle>
<par>For a particle of mass <inlinemath> <math> m<sub>x </sub> </math></inlinemath> traversing
a thickness of material <inlinemath> <math> &delta;x</math></inlinemath>,
the Landau probability distribution may be written in terms of the universal Landau
function <inlinemath> <math> &phi;(&lambda;)</math></inlinemath>
as<cite  
refid="bib-LAND"/>:
                         <eqnarray ><subeqn  
><math>f(&epsilon;,&delta;x)  =  <frac><nu>1</nu><!--
                                    --><de>&xi;</de></frac>&phi;(&lambda;)                         <mtext></mtext>
</math></subeqn></eqnarray>
where
             <eqnarray ><subeqn  
><math>&phi;(&lambda;)  =   <frac><nu>1</nu><!--_
--><de>2&pi;i</de></frac>&int;
                           <sub>
c+i&infin;</sub><sup>c-i&infin;</sup>exp<left>(</left>uln u+&lambda;u<right>)</right>du<hspace dim="2cm"/>c&geq;0             <mtext></mtext>
                 </math></subeqn><subeqn  
><math>
                </math></subeqn><subeqn  
><math>&lambda;  =  <frac><nu>&epsilon;-&macr;&epsilon; </nu> <!--
                        --><de>&xi;</de></frac> -&gamma;&prime; -&beta;<sup>2 </sup> -ln   <frac> <nu> &xi;</nu><!-- ___
--><de>E<sub><mathrm>max </mathrm> </sub> </de> </frac>                          <mtext></mtext>
                 </math></subeqn><subeqn  
><math>
               </math></subeqn><subeqn  
><math>&gamma;&prime;  =  0.422784... =1-&gamma;                              <mtext></mtext>
                 </math></subeqn><subeqn  
><math>
                </math></subeqn><subeqn  
><math>&gamma;  =  0.577215... (Euler's constant)                    <mtext></mtext>
                 </math></subeqn><subeqn  
><math>
                </math></subeqn><subeqn  
><math>&macr;&epsilon;  =  average energy loss                            <mtext></mtext>
                 </math></subeqn><subeqn  
><math>
                </math></subeqn><subeqn  
><math>&epsilon;  =  actual energy loss                             <mtext></mtext>
</math></subeqn></eqnarray>
</par>
<subsection >
<stitle>
Restrictions</stitle>
<par>The Landau formalism makes two restrictive assumptions :
</par><lalist  class="enumerate">
<item>
<par>The typical energy loss is small compared to the maximum energy loss in a
single collision. This restriction is removed in the Vavilov theory (see section <ref  
refid="vavref"/> ).
</par></item>
<item>
<par>The typical energy loss in the absorber should be large compared to the binding
energy of the most tightly bound electron. For gaseous detectors, typical energy
losses are a few keV which is comparable to the binding energies of the inner
electrons. In such cases a more sophisticated approach which accounts for atomic
energy levels<cite  
refid="bib-TALM"/> is necessary to accurately simulate data distributions. In <texttt> GEANT</texttt>,
a parameterised model by L. Urb&aacute;n is used (see section <ref  
refid="urban"/> ).</par></item></lalist>
<par>In addition, the average value of the Landau distribution is infinite.
Summing the Landau fluctuation obtained to the average energy from the
<inlinemath><math>dE/dx</math></inlinemath>
tables, we obtain a value which is larger than the one coming from the table. The
probability to sample a large value is small, so it takes a large number of steps
(extractions) for the average fluctuation to be significantly larger than zero. This
introduces a dependence of the energy loss on the step size which can affect
calculations.
</par><par>A solution to this has been to introduce a limit on the value of the
variable sampled by the Landau distribution in order to keep the average
fluctuation to 0. The value obtained from the <texttt> GLANDO</texttt> routine is:
<displaymath><math>
                  &delta;dE/dx=&epsilon;-&macr;&epsilon; =&xi;(&lambda;-&gamma;&prime; +&beta;<sup>2 </sup> +ln   <frac> <nu> &xi;</nu><!-- ___
--><de>E<sub><mathrm>max </mathrm> </sub> </de> </frac> )
</math></displaymath>
In order for this to have average 0, we must impose that:
<displaymath><math>
                        &macr;&lambda;=-&gamma;&prime; -&beta;<sup>2 </sup> -ln   <frac> <nu> &xi;</nu><!-- ___
--><de>E<sub><mathrm>max </mathrm> </sub> </de> </frac>
</math></displaymath>
</par><par>This is realised introducing a <inlinemath> <math> &lambda;<sub><mathrm>max </mathrm> </sub> (&macr;&lambda; )</math></inlinemath>
such that if only values of <inlinemath> <math> &lambda;&leq;&lambda;<sub><mathrm>max </mathrm> </sub> </math></inlinemath>
are accepted, the average value of the distribution is
<inlinemath><math>&macr;&lambda;</math></inlinemath>.
</par><par>A parametric fit to the universal Landau distribution has been performed, with following result:
<displaymath><math>
    &lambda;<sub><mathrm>max </mathrm> </sub> =0.60715+1.1934&macr;&lambda; +(0.67794+0.052382&macr;&lambda; )exp (0.94753+0.74442&macr;&lambda; )
</math></displaymath> only values
smaller than <inlinemath> <math> &lambda;<sub><mathrm>max </mathrm> </sub> </math></inlinemath>
are accepted, otherwise the distribution is resampled.
</par>
</subsection>
</section>
<section id="vavref">
<stitle>
Vavilov theory</stitle>
<par>Vavilov<cite  
refid="bib-VAVI"/> derived a more accurate straggling distribution by introducing the kinematic
limit on the maximum transferable energy in a single collision, rather than using
<inlinemath><math>E<sub><mathrm>max </mathrm> </sub> =&infin;</math></inlinemath>. Now
we can write<cite  
refid="bib-SCH1"/>:
                      <eqnarray ><subeqn  
><math>f<left>( </left> &epsilon;,&delta;s<right>) </right>  =  <frac><nu>1</nu><!--
                                 --><de>&xi;</de></frac>&phi;<sub>v</sub> <left> &parenleftbig;
   </left> &lambda;<sub>v</sub> ,&kappa;,&beta;<sup>2 </sup> <right> &parenrightbig; </right>                      <mtext></mtext>
</math></subeqn></eqnarray>
where
        <eqnarray ><subeqn  
><math>&phi;<sub>v</sub> <left> &parenleftbig;
   </left> &lambda;<sub>v</sub> ,&kappa;,&beta;<sup>2 </sup> <right> &parenrightbig; </right>  =   <frac><nu>1</nu><!--_
--><de>2&pi;i</de></frac>&int;
                            <sub>
c+i&infin;</sub><sup>c-i&infin;</sup>&phi;<left>( </left> s<right>) </right> e<sup>&lambda;s </sup> ds<hspace dim="2cm"/>c&geq;0                   <mtext></mtext>
                  </math></subeqn><subeqn  
><math>
              </math></subeqn><subeqn  
><math>&phi;<left>( </left> s<right>) </right>  =  exp<left>&bracketleftbig;
                           </left>&kappa;(1+&beta;<sup>2 </sup> &gamma;)<right>&bracketrightbig;</right>exp<left>[</left>&psi;<left>( </left> s<right>) </right> <right> ]</right>,                      <mtext></mtext>
                  </math></subeqn><subeqn  
><math>
              </math></subeqn><subeqn  
><math>&psi;<left>( </left> s<right>) </right>  =  sln &kappa;+(s+&beta;<sup>2 </sup> &kappa;)<left>[ </left> ln (s/&kappa;)+E<sub>
1 </sub> (s/&kappa;)<right>] </right> -&kappa;e<sup>-s/&kappa; </sup> ,        <mtext></mtext>
</math></subeqn></eqnarray>
and
            <eqnarray ><subeqn  
><math>E<sub>1 </sub> (z)  =  &int;
                        <sub>
&infin;</sub><sup>z</sup>t<sup>-1 </sup> e<sup>-t </sup> dt<hspace dim="1cm"/>(the exponential integral)            <mtext></mtext>
                </math></subeqn><subeqn  
><math>
              </math></subeqn><subeqn  
><math>&lambda;<sub>v</sub>  =  &kappa;<left>&bracketleftbigg;
  </left><frac> <nu> &epsilon;-&macr;&epsilon; </nu> <!-- 
  --><de>&xi;</de></frac>  -&gamma;&prime; -&beta;<sup>2 </sup> <right> &bracketrightbigg;
                   </right>                               <mtext></mtext>
</math></subeqn></eqnarray>
</par><par>The Vavilov parameters are simply related to the Landau parameter by
<inlinemath><math>&lambda;<sub>L </sub> =&lambda;<sub>v</sub> /&kappa;-ln &kappa;</math></inlinemath>. It can be shown that
as <inlinemath> <math> &kappa;&arrowright;0</math></inlinemath>, the distribution of
the variable <inlinemath> <math> &lambda;<sub>L </sub> </math></inlinemath> approaches
that of Landau. For <inlinemath> <math> &kappa;&leq;0.01</math></inlinemath>
the two distributions are already practically identical. Contrary to what many textbooks
report, the Vavilov distribution <emph> does not</emph> approximate the Landau distribution for small
<inlinemath><math>&kappa;</math></inlinemath>, but rather the
distribution of <inlinemath> <math> &lambda;<sub>L </sub> </math></inlinemath>
defined above tends to the distribution of the true
<inlinemath><math>&lambda;</math></inlinemath> from
the Landau density function. Thus the routine <texttt> GVAVIV</texttt> samples the variable
<inlinemath><math>&lambda;<sub>L </sub> </math></inlinemath> rather
than <inlinemath> <math> &lambda;<sub>v</sub> </math></inlinemath>.
For <inlinemath> <math> &kappa;&geq;10</math></inlinemath>
the Vavilov distribution tends to a Gaussian distribution (see next section).
</par>
</section>
<section >
<stitle>
Gaussian Theory</stitle>
<par>Various conflicting forms have been proposed for Gaussian straggling functions, but most
of these appear to have little theoretical or experimental basis. However, it has been shown<cite  
refid="bib-SELT"/>
that for <inlinemath> <math> &kappa;&geq;10</math></inlinemath>
the Vavilov distribution can be replaced by a Gaussian of the form :
           <eqnarray ><subeqn  
><math>f(&epsilon;,&delta;s)&approxequal;        <frac> <nu> 1</nu><!--________
--><de>&xi;<sqrt><frac> <nu> 2&pi;</nu><!-- 
 --><de>&kappa;</de></frac> <left> ( </left> 1-&beta;<sup>2 </sup> /2<right>) </right> </sqrt> </de> </frac>exp <left> &bracketleftbigg;
                        </left><frac> <nu> (&epsilon;-&macr;&epsilon; )<sup>2 </sup> </nu> <!-- 
    --><de>2</de></frac>           <frac> <nu> &kappa;</nu><!-- _______
--><de>&xi;<sup>2 </sup> (1-&beta;<sup>2 </sup> /2)</de></frac><right> &bracketrightbigg;
                                                   </right>               <mtext></mtext>
</math></subeqn></eqnarray>
thus implying
                <eqnarray ><subeqn  
><math><mathrm>mean</mathrm>  =  &macr;&epsilon;                                       <mtext></mtext>
                    </math></subeqn><subeqn  
><math>
                  </math></subeqn><subeqn  
><math>&sigma;<sup>2 </sup>  =  <frac><nu>&xi;<sup>2 </sup> </nu> <!--
                          --><de>&kappa;</de></frac> (1-&beta;<sup>2 </sup> /2)=&xi;E<sub><mathrm>
max </mathrm> </sub> (1-&beta;<sup>2 </sup> /2)                <mtext></mtext>
</math></subeqn></eqnarray>
</par>
</section>
<section id="urban">
<stitle>
Urb&aacute;n model</stitle>
<par>The method for computing restricted energy losses with
<inlinemath><math>&delta;</math></inlinemath>-ray
production above given threshold energy in <texttt> GEANT</texttt> is a Monte Carlo method that
can be used for thin layers. It is fast and it can be used for any thickness of a
medium. Approaching the limit of the validity of Landau's theory, the loss
distribution approaches smoothly the Landau form as shown in Figure <ref  
refid="fg:phys332-2"/> .
</par><figure>
<includegraphics file="phys332-2"/>
<!--Figure 2--><caption id="fg:phys332-2">Energy loss distribution for a 3 GeV electron in Argon as given by
standard <texttt> GEANT</texttt>. The width of the layers is given in centimeters.</caption>
</figure>
<par>It is assumed that the atoms have only two energy levels with binding energy
<inlinemath><math>E<sub>1 </sub> </math></inlinemath> and
<inlinemath><math>E<sub>2 </sub> </math></inlinemath>.
The particle--atom interaction will then be an excitation with energy loss
<inlinemath><math>E<sub>1 </sub> </math></inlinemath> or
<inlinemath><math>E<sub>2 </sub> </math></inlinemath>, or
an ionisation with an energy loss distributed according to a function
<inlinemath><math>g(E)&similar;1/E<sup>2 </sup> </math></inlinemath>:
<equation ><math>
                        g(E)=<frac><nu>(E<sub><mathrm>max </mathrm> </sub> +I)I</nu><!--
    --><de>E<sub><mathrm>max </mathrm> </sub> </de> </frac>        <frac> <nu> 1</nu><!-- _
--><de>E<sup>2 </sup> </de> </frac>                      (1)
</math></equation>
</par><par>The macroscopic cross-section for excitations
(<inlinemath><math>i=1,2</math></inlinemath>) is
<equation id="eq:sigex"><math>
                   &Sigma;<sub>i </sub> =C <frac> <nu> f<sub>i </sub> </nu> <!-- 
--><de>E<sub>i </sub> </de> </frac> <frac> <nu> ln (2m&beta;<sup>2 </sup> &gamma;<sup>2 </sup> /E<sub>i </sub> )-&beta;<sup>2 </sup> </nu> <!-- 
 --><de>ln (2m&beta;<sup>2 </sup> &gamma;<sup>2 </sup> /I)-&beta;<sup>2 </sup> </de> </frac> (1-r)                (2)
</math></equation>and the macroscopic cross-section for ionisation is <equation id="eq:sigion"> <math>
                    &Sigma;<sub>3 </sub> =C            <frac> <nu> E<sub><mathrm>max </mathrm> </sub> </nu> <!-- ________________
--><de>I(E<sub><mathrm>max </mathrm> </sub> +I)ln (<frac><nu>E<sub><mathrm>max </mathrm> </sub> +I</nu><!-- 
      --><de>I</de></frac>      )</de></frac>r                  (3)
</math></equation><inlinemath><math>E<sub><mathrm>max </mathrm> </sub> </math></inlinemath> is the <texttt> GEANT</texttt> cut
for <inlinemath> <math> &delta;</math></inlinemath>-production,
or the maximum energy transfer minus mean ionisation energy, if it is smaller than
this cut-off value. The following notation is used:
</par><par><tabular preamble="ll"><row><cell  
><inlinemath><math>r,C</math></inlinemath></cell><cell  
>parameters of the model</cell>
</row><row><cell  
><inlinemath><math>E<sub>i </sub> </math></inlinemath></cell><cell  
>atomic energy levels      </cell>
</row><row><cell  
><inlinemath><math>I</math></inlinemath></cell><cell  
>mean ionisation energy  </cell>
</row><row><cell  
><inlinemath><math>f<sub>i </sub></math></inlinemath></cell><cell  
>oscillator strengths       </cell>
</row></tabular>
</par><par>The model has the parameters <inlinemath> <math> f<sub>i </sub> </math></inlinemath>,
<inlinemath><math>E<sub>i </sub> </math></inlinemath>,
<inlinemath><math>C</math></inlinemath> and
<inlinemath><math>r(0&leq;r&leq;1)</math></inlinemath>. The oscillator
strengths <inlinemath> <math> f<sub>i </sub> </math></inlinemath> and the
atomic level energies <inlinemath> <math> E<sub>i </sub> </math></inlinemath>
should satisfy the constraints
                              <eqnarray ><subeqn  
id="eq:fisum"><math>f<sub>1 </sub> +f<sub>2 </sub>  =  1                      <mtext>(4)</mtext>
                                   </math></subeqn><subeqn  
><math>
                      </math></subeqn><subeqn  
id="eq:flnsum"><math>f<sub>1 </sub> ln E<sub>1 </sub> +f<sub>2 </sub> ln E<sub>2 </sub>  =  lnI                    <mtext>(5)</mtext>
</math></subeqn></eqnarray>
The parameter <inlinemath> <math> C</math></inlinemath>
can be defined with the help of the mean energy loss
<inlinemath><math>dE/dx</math></inlinemath> in the following way: The
numbers of collisions (<inlinemath><math>n<sub>i </sub> </math></inlinemath>,
i = 1,2 for the excitation and 3 for the ionisation) follow the Poisson distribution with a mean
number <inlinemath> <math> &angbracketleft;n<sub>i </sub> &angbracketright;</math></inlinemath>.
In a step <inlinemath> <math> &Delta;x</math></inlinemath>
the mean number of collisions is <equation > <math>
                            &angbracketleft;n<sub>i </sub> &angbracketright;=&Sigma;<sub>i </sub> &Delta;x                          (6)
</math></equation>The mean energy loss <inlinemath> <math> dE/dx</math></inlinemath>
in a step is the sum of the excitation and ionisation contributions <equation > <math>
            <frac><nu>dE</nu><!--
            --><de>dx</de></frac> &Delta;x=<left>&bracketleftbigg;
  </left> &Sigma;<sub>1 </sub> E<sub>1 </sub> +&Sigma;<sub>2 </sub> E<sub>2 </sub> +&Sigma;<sub>3 </sub> &int;
    <sub> I</sub> <sup> E<sub><mathrm>max </mathrm> </sub> +I</sup> Eg(E)dE<right>&bracketrightbigg;
                                                    </right> &Delta;x         (7)
</math></equation>From this, using the equations (<ref  
refid="eq:sigex"/>), (<ref  
refid="eq:sigion"/>), (<ref  
refid="eq:fisum"/>) and (<ref  
refid="eq:flnsum"/>), one can define the parameter
<inlinemath><math>C</math></inlinemath>
<equation ><math>
                              C=<frac><nu>dE</nu><!--
--><de>dx</de></frac>                            (8)
</math></equation>
</par><par>The following values have been chosen in <texttt> GEANT</texttt> for the other parameters:
<displaymath><math>
                   f<sub>2 </sub> =<left>&bracelefttp;
&braceleftmid;
&braceleftbt; </left> 0    <mathrm> if</mathrm> Z&leq;2
   2/Z<mathrm> if</mathrm> Z&gt;2 <right></right>&arrowdblright;f<sub>1 </sub> =1-f<sub>2 </sub>
                   E<sub>2 </sub> =10Z<sup>2 </sup> <mathrm> eV </mathrm>    &arrowdblright;E<sub>1 </sub> =<left>&parenleftBig;
  </left>  <frac> <nu> I</nu><!-- ___
--><de>E<sub>2 </sub> <sup> f<sub>2 </sub> </sup> </de> </frac> <right> &parenrightBig;
          </right> <sup> <frac> <nu> 1</nu><!-- _
--><de>f<sub>1 </sub> </de> </frac> </sup>
                   r=0.4
</math></displaymath> With these values
the atomic level <inlinemath> <math> E<sub>2 </sub> </math></inlinemath>
corresponds approximately the K-shell energy of the atoms and
<inlinemath><math>Zf<sub>2 </sub> </math></inlinemath> the number of
K-shell electrons. <inlinemath> <math> r</math></inlinemath>
is the only variable which can be tuned freely. It determines the relative contribution
of ionisation and excitation to the energy loss.
</par><par>The energy loss is computed with the assumption that the step length (or the relative
energy loss) is small, and---in consequence---the cross-section can be considered
constant along the path length. The energy loss due to the excitation is
<equation ><math>
                         &Delta;E<sub>e </sub> =n<sub>1 </sub> E<sub>1 </sub> +n<sub>2 </sub> E<sub>2 </sub>                       (9)
</math></equation>where <inlinemath> <math> n<sub>1 </sub> </math></inlinemath>
and <inlinemath> <math> n<sub>2 </sub> </math></inlinemath>
are sampled from Poisson distribution as discussed above. The
loss due to the ionisation can be generated from the distribution
<inlinemath><math>g(E)</math></inlinemath> by
the inverse transformation method:
                       <eqnarray ><subeqn  
><math>u=F(E)  =  &int;
                                     <sub>
I</sub><sup>E</sup>g(x)dx                     <mtext></mtext>
                              </math></subeqn><subeqn  
><math>
                     </math></subeqn><subeqn  
><math>E=F<sup>-1 </sup> (u)  =       <frac><nu>I</nu><!--____
--><de>1-u  <frac> <nu> E<sub><mathrm>max </mathrm> </sub> </nu> <!-- ___
--><de>E<sub><mathrm>max </mathrm> </sub> +I</de></frac> </de> </frac>                 <mtext>(10)</mtext>
                              </math></subeqn><subeqn  
><math>
                              </math></subeqn><subeqn  
><math>                                 <mtext>(11)</mtext>
</math></subeqn></eqnarray>
where <inlinemath> <math> u</math></inlinemath> is a uniform
random number between <inlinemath> <math> F(I)=0</math></inlinemath>
and <inlinemath> <math> F(E<sub><mathrm>max </mathrm> </sub> +I)=1</math></inlinemath>.
The contribution from the ionisations will be <equation > <math>
                     &Delta;E<sub>i </sub> =&sum;
    <sub> j=1 </sub> <sup> n<sub>3 </sub>
                </sup>           <frac> <nu> I</nu><!-- ________
--><de>1-u<sub>j</sub>   <frac> <nu> E<sub><mathrm>max </mathrm> </sub> </nu> <!-- ___
--><de>E<sub><mathrm>max </mathrm> </sub> +I</de></frac> </de> </frac>                  (12)
</math></equation>where <inlinemath> <math> n<sub>3 </sub> </math></inlinemath> is the
number of ionisation (sampled from Poisson distribution). The energy loss in a step will
then be <inlinemath> <math> &Delta;E=&Delta;E<sub>e </sub> +&Delta;E<sub>i </sub> </math></inlinemath>.
</par>
<subsection >
<stitle>
Fast simulation for <inlinemath> <math> n<sub>3 </sub> &geq;16</math></inlinemath></stitle>
<par>If the number of ionisation <inlinemath> <math> n<sub>3 </sub> </math></inlinemath>
is bigger than 16, a faster sampling method can be used. The possible energy loss
interval is divided in two parts: one in which the number of collisions is large and the
sampling can be done from a Gaussian distribution and the other in which
the energy loss is sampled for each collision. Let us call the former interval
<inlinemath><math>[I,&alpha;I]</math></inlinemath> the interval A,
and the latter <inlinemath> <math> [&alpha;I,E<sub><mathrm>max </mathrm> </sub> ]</math></inlinemath> the
interval B. <inlinemath> <math> &alpha;</math></inlinemath> lies
between 1 and <inlinemath> <math> E<sub><mathrm>max </mathrm> </sub> /I</math></inlinemath>.
A collision with a loss in the interval A happens with the probability <equation id="eq:phys332-5"> <math>
                 P(&alpha;)=&int;
   <sub> I</sub> <sup> &alpha;I</sup> g(E)dE=<frac><nu>(E<sub><mathrm>max </mathrm> </sub> +I)(&alpha;-1)</nu><!--
      --><de>E<sub><mathrm>max </mathrm> </sub> &alpha;</de></frac>                  (13)
</math></equation>The mean energy loss and the standard deviation for this type of collision are
<equation ><math>
                &angbracketleft;&Delta;E(&alpha;)&angbracketright;=   <frac> <nu> 1</nu><!--___
--><de>P(&alpha;)</de></frac>&int;
          <sub> I</sub> <sup> &alpha;I</sup> Eg(E)dE=<frac><nu>I&alpha;ln &alpha;</nu><!--
 --><de>&alpha;-1</de></frac>              (14)
</math></equation>and <equation > <math>
             &sigma;<sup>2 </sup> (&alpha;)=   <frac> <nu> 1</nu><!--___
--><de>P(&alpha;)</de></frac>&int;
          <sub> I</sub> <sup> &alpha;I</sup> E<sup>2 </sup> g(E)dE=I<sup>2 </sup> &alpha;<left>&parenleftbigg;
  </left> 1- <frac> <nu> &alpha;ln <sup> 2 </sup> &alpha;</nu><!--_
--><de>(&alpha;-1)<sup>2 </sup> </de> </frac><right> &parenrightbigg;
                   </right>         (15)
</math></equation>If the collision number is high , we assume that the number of the type A collisions
can be calculated from a Gaussian distribution with the following mean value and
standard deviation:
                     <eqnarray ><subeqn  
id="eq:phys332-1"><math>&angbracketleft;n<sub>A </sub> &angbracketright;  =  n<sub>3 </sub> P(&alpha;)                          <mtext>(16)</mtext>
                         </math></subeqn><subeqn  
><math>
                      </math></subeqn><subeqn  
id="eq:phys332-2"><math>&sigma;<sub>A </sub> <sup> 2 </sup>  =  n<sub>
3 </sub> P(&alpha;)(1-P(&alpha;))                  <mtext>(17)</mtext>
</math></subeqn></eqnarray>
It is further assumed that the energy loss in these collisions has a Gaussian
distribution with
                       <eqnarray ><subeqn  
id="eq:phys332-3"><math>&angbracketleft;&Delta;E<sub>A </sub> &angbracketright;  =  n<sub>A </sub> &angbracketleft;&Delta;E(&alpha;)&angbracketright;                   <mtext>(18)</mtext>
                            </math></subeqn><subeqn  
><math>
                        </math></subeqn><subeqn  
id="eq:phys332-4"><math>&sigma;<sub>E,A </sub> <sup> 2 </sup>  =  n<sub>
A </sub> &sigma;<sup>2 </sup> (&alpha;)                      <mtext>(19)</mtext>
</math></subeqn></eqnarray>
The energy loss of these collision can then be sampled from the Gaussian
distribution.
</par><par>The collisions where the energy loss is in the interval B are sampled directly from
<equation ><math>
                  &Delta;E<sub>B</sub> =&sum;
    <sub> i=1 </sub> <sup> n<sub>3 </sub> -n<sub>A </sub>
                                </sup>                  <frac> <nu> &alpha;I</nu><!-- _________
--><de>1-u<sub>i </sub> <frac> <nu> E<sub><mathrm>max </mathrm> </sub> +I-&alpha;I</nu><!-- 
   --><de>E<sub><mathrm>max </mathrm> </sub> +I</de></frac>    </de> </frac>               (20)
</math></equation>The total energy loss is the sum of these two types of collisions: <equation > <math>
                          &Delta;E=&Delta;E<sub>A </sub> +&Delta;E<sub>B</sub>                      (21)
</math></equation>
</par><par>The approximation of equations ((<ref  
refid="eq:phys332-1"/>), (<ref  
refid="eq:phys332-2"/>), (<ref  
refid="eq:phys332-3"/>) and (<ref  
refid="eq:phys332-4"/>) can be used under the following
conditions:
                           <eqnarray ><subeqn  
id="eq:phys332-6"><math>&angbracketleft;n<sub>A </sub> &angbracketright;-c&sigma;<sub>A </sub>  &geq;  0                     <mtext>(22)</mtext>
                                   </math></subeqn><subeqn  
><math>
                           </math></subeqn><subeqn  
id="eq:phys332-7"><math>&angbracketleft;n<sub>A </sub> &angbracketright;+c&sigma;<sub>A </sub>  &leq;  n<sub>3 </sub>                    <mtext>(23)</mtext>
                                   </math></subeqn><subeqn  
><math>
                       </math></subeqn><subeqn  
id="eq:phys332-8"><math>&angbracketleft;&Delta;E<sub>A </sub> &angbracketright;-c&sigma;<sub>E,A </sub>  &geq;  0                     <mtext>(24)</mtext>
</math></subeqn></eqnarray>
where <inlinemath> <math> c&geq;4</math></inlinemath>.
From the equations (<ref  
refid="eq:phys332-5"/>), (<ref  
refid="eq:phys332-1"/>) and (<ref  
refid="eq:phys332-3"/>) and from the conditions (<ref  
refid="eq:phys332-6"/>) and (<ref  
refid="eq:phys332-7"/>) the following limits
can be derived: <equation > <math>
          &alpha;<sub><mathrm>min </mathrm> </sub> =<frac><nu>(n<sub>3 </sub> +c<sup>2 </sup> )(E<sub><mathrm>max </mathrm> </sub> +I)</nu><!--
--><de>n<sub>3 </sub> (E<sub><mathrm>max </mathrm> </sub> +I)+c<sup>2 </sup> I</de></frac> &leq;&alpha;&leq;&alpha;<sub><mathrm>max </mathrm> </sub> =<frac><nu>(n<sub>3 </sub> +c<sup>2 </sup> )(E<sub><mathrm>max </mathrm> </sub> +I)</nu><!--
--><de>c<sup>2 </sup> (E<sub><mathrm>max </mathrm> </sub> +I)+n<sub>3 </sub> I</de></frac>       (25)
</math></equation>This conditions gives a lower limit to number of the ionisations
<inlinemath><math>n<sub>3 </sub> </math></inlinemath> for
which the fast sampling can be done: <equation > <math>
                              n<sub>3 </sub> &geq;c<sup>2 </sup>                           (26)
</math></equation>As in the conditions (<ref  
refid="eq:phys332-6"/>), (<ref  
refid="eq:phys332-7"/>) and (<ref  
refid="eq:phys332-8"/>) the value of
<inlinemath><math>c</math></inlinemath> is as minimum
4, one gets <inlinemath> <math> n<sub>3 </sub> &geq;16</math></inlinemath>.
In order to speed the simulation, the maximum value is used for
<inlinemath><math>&alpha;</math></inlinemath>.
</par><par>The number of collisions with energy loss in the interval B (the number of interactions
which has to be simulated directly) increases slowly with the total number of collisions
<inlinemath><math>n<sub>3 </sub> </math></inlinemath>. The
maximum number of these collisions can be estimated as <equation > <math>
                   n<sub>B,max </sub> =n<sub>3 </sub> -n<sub>A,min </sub> &approxequal;n<sub>3 </sub> (&angbracketleft;n<sub>A </sub> &angbracketright;-&sigma;<sub>A </sub> )               (27)
</math></equation>From the previous expressions for <inlinemath> <math> &angbracketleft;n<sub>A </sub> &angbracketright;</math></inlinemath>
and <inlinemath> <math> &sigma;<sub>A </sub> </math></inlinemath>
one can derive the condition <equation > <math>
                         n<sub>B</sub> &leq;n<sub>B,max </sub> = <frac> <nu> 2n<sub>3 </sub> c<sup>2 </sup> </nu> <!--_
--><de>n<sub>3 </sub> +c<sup>2 </sup> </de> </frac>                     (28)
</math></equation>The following values are obtained with
<inlinemath><math>c=4</math></inlinemath>:
</par><par><tabular preamble="llcrr"><row><cell  
><inlinemath><math>n<sub>3 </sub> </math></inlinemath></cell><cell  
><inlinemath><math>n<sub>B,max </sub> </math></inlinemath></cell><cell  
></cell><cell  
><inlinemath><math>n<sub>3 </sub> </math></inlinemath></cell><cell  
><inlinemath><math>n<sub>B,max </sub> </math></inlinemath></cell>
</row><row><cell  
>16                                                                                                     </cell><cell  
>16                                                                                                     </cell><cell  
></cell><cell  
>                                                               200</cell><cell  
>                                                             29.63</cell>
</row><row><cell  
>20                                                                                                     </cell><cell  
>17.78                                                                                                 </cell><cell  
></cell><cell  
>                                                               500</cell><cell  
>                                                             31.01</cell>
</row><row><cell  
>50                                                                                                     </cell><cell  
>24.24                                                                                                 </cell><cell  
></cell><cell  
>                                                              1000</cell><cell  
>                                                             31.50</cell>
</row><row><cell  
>100                                                                                                   </cell><cell  
>27.59                                                                                                 </cell><cell  
></cell><cell  
><inlinemath><math>&infin;</math></inlinemath></cell><cell  
>                                                             32.00</cell>
</row></tabular>
</par>
</subsection>
<subsection >
<stitle>
Special sampling for lower part of the spectrum</stitle>
<par>If the step length is very small (<inlinemath><math>&leq;5</math></inlinemath>
mm in gases, <inlinemath> <math> &leq;</math></inlinemath>
2-3 <inlinemath> <math> &mu;</math></inlinemath>m
in solids) the model gives 0 energy loss for some events. To avoid this, the probability
of 0 energy loss is computed <equation > <math>
                     P(&Delta;E=0)=e<sup>-(&angbracketleft;n<sub>1 </sub> &angbracketright;+&angbracketleft;n<sub>2 </sub> &angbracketright;+&angbracketleft;n<sub>3 </sub> &angbracketright;) </sup>                 (29)
</math></equation>If the probability is bigger than 0.01 a special sampling is done, taking into account the fact
that in these cases the projectile interacts only with the outer electrons of the atom. An
energy level <inlinemath> <math> E<sub>0 </sub> =10</math></inlinemath>
eV is chosen to correspond to the outer electrons. The mean number of collisions can
be calculated from <equation > <math>
                           &angbracketleft;n&angbracketright;= <frac> <nu> 1</nu><!--_
--><de>E<sub>0 </sub> </de> </frac> <frac> <nu> dE</nu><!-- 
--><de>dx</de></frac> &Delta;x                       (30)
</math></equation>The number of collisions <inlinemath> <math> n</math></inlinemath>
is sampled from Poisson distribution. In the case of the thin layers, all the
collisions are considered as ionisations and the energy loss is computed as
<equation ><math>
                      &Delta;E=&sum;
    <sub> i=1 </sub> <sup> n </sup>           <frac> <nu> E<sub>0 </sub> </nu> <!-- _________
--><de>1-   <frac> <nu> E<sub><mathrm>max </mathrm> </sub> </nu> <!-- _____
--><de>E<sub><mathrm>max </mathrm> </sub> +E<sub>0 </sub> </de> </frac> u<sub>i </sub> </de> </frac>                  (31)
</math></equation>
</par>
</subsection>
</section>
<section class="star">
<stitle>
References</stitle>
   <bibliography >
   <bibitem id="bib-LAND">
   <par>L.Landau.  On the Energy Loss of Fast Particles by Ionisation.  Originally
   published  in  <emph> J.  Phys.</emph>,  8:201,  1944.    Reprinted  in  D.ter  Haar,  Editor,
   <emph>L.D.Landau, Collected papers</emph>, page 417. Pergamon Press, Oxford, 1965.
   </par></bibitem>
   <bibitem id="bib-SCH1">
   <par>B.Schorr.  Programs for the Landau and the Vavilov distributions and the
   corresponding random numbers. <emph> Comp. Phys. Comm.</emph>, 7:216, 1974.
   </par></bibitem>
   <bibitem id="bib-SELT">
   <par>S.M.Seltzer and M.J.Berger. Energy loss straggling of protons and mesons.
   In <emph> Studies in Penetration of Charged Particles in Matter</emph>, Nuclear Science
   Series 39, Nat. Academy of Sciences, Washington DC, 1964.
   </par></bibitem>
   <bibitem id="bib-TALM">
   <par>R.Talman. On the statistics of particle identification using ionization. <emph> Nucl.
   Inst. Meth.</emph>, 159:189, 1979.
   </par></bibitem>
   <bibitem id="bib-VAVI">
   <par>P.V.Vavilov. Ionisation losses of high energy heavy particles. <emph> Soviet Physics
   JETP</emph>, 5:749, 1957.</par></bibitem></bibliography>
</section>
</bodymatter></document>

