[pstricks] The outside of a closed curve

[Herbert Voss]

Am 06.12.2009 22:38, schrieb Jon Joseph:
> I have the following code
> 
> \begin{pspicture}(0,0)(5,4)
> 	\multido{\rx=1.45+0.45}{7} 
> 	{
> 		\psline(\rx,0)(\rx,4)
> 	}
> 	\psccurve[showpoints=false, linewidth=2pt](1,2)(1.4,2.6)(2,2.95)(2.8,3.55)(3.4,3.75)(4,3.6)(4.5,3)(4.6,2.6)(4.45,2.0)(4,1.35)(3.3,1.0)(2.6,0.9)(2.0,1.1)(1.4,1.4)
> \end{pspicture}
> 
> And I would the lines to be clipped outside the curve. The psccurve* option of course fills the inside of the curve. Is there a method to "fill" outside the curve out to the edges of the picture so I don't have to calculate where the lines intersect the curve? (i.e. I only want the vertical lines to be visible inside the curve).  Thanks, Jon.

you can clip but it easier to use an ordinary fill style

\documentclass{minimal}
\usepackage{multido}
\usepackage{pstricks}

\begin{document}
\begin{pspicture}(0,0)(5,4)
\psclip{\psccurve[showpoints=false, linewidth=2pt]
	(1,2)(1.4,2.6)(2,2.95)(2.8,3.55)(3.4,3.75)
	(4,3.6)(4.5,3)(4.6,2.6)(4.45,2.0)(4,1.35)
	(3.3,1.0)(2.6,0.9)(2.0,1.1)(1.4,1.4)}
  \multido{\rx=1.45+0.45}{7}{\psline(\rx,0)(\rx,4)}
\endpsclip
\end{pspicture}

\begin{pspicture}(0,0)(5,4)
\psccurve[linewidth=2pt,fillstyle=hlines,hatchangle=90,hatchsep=0.45]
	(1,2)(1.4,2.6)(2,2.95)(2.8,3.55)(3.4,3.75)
	(4,3.6)(4.5,3)(4.6,2.6)(4.45,2.0)(4,1.35)
	(3.3,1.0)(2.6,0.9)(2.0,1.1)(1.4,1.4)
\end{pspicture}

\end{document}

Herbert